in parallelogram ABCD angle a =Angle B + 50° find all the angles of quadrilateral ABCD
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x+x+50+x+x+50= 360
4x+100=360
4x=260
x=260\4
x=65
a=x=65
b=x+50=115
c=x=65
d=115
it is so simple yar
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