In parallelogram ABCD, ANGLE B-Angle A =40 find all the angles of parallelogram ABCD
Answers
Answered by
33
hey here is your answer
Answer:
Angles of parallelogram in order are 110°, 70°, 110°, 70°.
Step-by-step explanation:
Hi,
Given a parallelogram ABCD in which
∠ B - ∠ A = 40° --------------------(1).
But, we know adjacent angles in a parallelogram are supplementary
Hence, ∠ B + ∠ A = 180° -------(2)
From (1) and (2) , we get
∠ B = 110° and ∠ A = 70°.
Also, we know that opposite angles in a parallelogram are equal.
Hence, ∠ C = ∠ A = 70° and
∠ D = ∠ B = 110°
Thus the angles of parallelogram in order are 110°, 70°, 110°, 70°.
Hope, it helps !
make sure it brainliest please
Answer:
Angles of parallelogram in order are 110°, 70°, 110°, 70°.
Step-by-step explanation:
Hi,
Given a parallelogram ABCD in which
∠ B - ∠ A = 40° --------------------(1).
But, we know adjacent angles in a parallelogram are supplementary
Hence, ∠ B + ∠ A = 180° -------(2)
From (1) and (2) , we get
∠ B = 110° and ∠ A = 70°.
Also, we know that opposite angles in a parallelogram are equal.
Hence, ∠ C = ∠ A = 70° and
∠ D = ∠ B = 110°
Thus the angles of parallelogram in order are 110°, 70°, 110°, 70°.
Hope, it helps !
make sure it brainliest please
tejnagpal:
sweet and simple
Answered by
23
B=A+40
since, B+C=180
so, C=180-B=140-A
since, C+D=180
so, D=180-C=40+A
now,
as A+B+C+D=360
A+40+A+140-A+40+A=360
220+2A=360
A=70
SO, B=110
C=70
D=110
THANKU
please follow my YouTube Chanel
Tej nagpal
since, B+C=180
so, C=180-B=140-A
since, C+D=180
so, D=180-C=40+A
now,
as A+B+C+D=360
A+40+A+140-A+40+A=360
220+2A=360
A=70
SO, B=110
C=70
D=110
THANKU
please follow my YouTube Chanel
Tej nagpal
Similar questions