Math, asked by bhavesh4305, 1 year ago

In parallelogram ABCD, ANGLE B-Angle A =40 find all the angles of parallelogram ABCD

Answers

Answered by sweetandsimple64
33
hey here is your answer

Answer:

Angles of parallelogram in order are 110°, 70°, 110°, 70°.

Step-by-step explanation:

Hi,

Given a parallelogram ABCD in which

∠ B - ∠ A = 40° --------------------(1).

But, we know adjacent angles in a parallelogram are supplementary

Hence, ∠ B + ∠ A = 180° -------(2)

From (1) and (2) , we get

∠ B = 110° and  ∠ A = 70°.

Also, we know that opposite angles in a parallelogram are equal.

Hence, ∠ C = ∠ A = 70° and

∠ D = ∠ B = 110°

Thus the angles of parallelogram in order are 110°, 70°, 110°, 70°.

Hope, it helps !

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Answered by tejnagpal
23
B=A+40
since, B+C=180
so, C=180-B=140-A
since, C+D=180
so, D=180-C=40+A
now,
as A+B+C+D=360
A+40+A+140-A+40+A=360
220+2A=360
A=70
SO, B=110
C=70
D=110
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