Question

In parallelogram ABCD, B-A = 40°. Find all the angles of parallelogram
ABCD.​

Answer 1

Answer:

ANSWER

ABCD is a parallelogram

Given ∠DAB=∠BCD=40

0

and AD∥BC

We know that sum of consecutive angle are 180

0

∠CBA+∠DAB=180

0

∴∠CBA=180−40=140

0

We know that in parallelogram opposite angles are equal

Then ∠ADC=∠CBA=140

0

So angles of parallelogram are 40

0

,140

0

,40

0

,140

0

Answer 2

ABCD is a parallelogram

Given ∠DAB=∠BCD=400 and AD∥BC

We know that sum of consecutive angle are 1800

∠CBA+∠DAB=1800

∴∠CBA=180−40=1400

We know that in parallelogram opposite angles are equal

Then ∠ADC=∠CBA=1400

So angles of parallelogram are 400,1400,400,1400.