in parallelogram ABCD ,bisector of angle D to line segment AB in P,AD=4,AB=9 find BP
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By Pythagoras method
(BP)2=(AB)2+(AD)2
(Bp)2=(9)2+(4)2
=81+16
(BP)2=97
BP=9.84
(BP)2=(AB)2+(AD)2
(Bp)2=(9)2+(4)2
=81+16
(BP)2=97
BP=9.84
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