In parallelogram ABCD, E and F are any two points on the side AB and BC respectively. Show that
ar( △ADF)=ar( △DCE)
(hint- draw EG| |AD, FH| |AB)
Answers
Answered by
6
Triangle DCE and parallelogram ABCD are on the same base and between the same parallels
Therefore ar(DCE)=1/2 ar(ABCD)...(1)
Similarly
ar(ADF)=1/2 ar(ABCD)...(2)
From 1 and 2 we get
ar(ADF)=ar(DCE)
Therefore ar(DCE)=1/2 ar(ABCD)...(1)
Similarly
ar(ADF)=1/2 ar(ABCD)...(2)
From 1 and 2 we get
ar(ADF)=ar(DCE)
Similar questions
Science,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago
English,
1 year ago