Question

in parallelogram ABCD find 3x-2, 50-x​

Answer 1

Answer:

37° , 143° , 37° and 143°

Step-by-step explanation:

In a parallelogram, opposite angles are equal.

So, 3x - 2 = 50 - x

⇒ 3x + x = 50 + 2

⇒ 4x = 52  

⇒ x = 13  

3x - 2 = (3 * 13) - 2 = 39 - 2 = 37°  

∠A  = ∠C = 37°  

The sum of all angles of a parallelogram is equal to 360°.

∠A + ∠B + ∠C + ∠D = 360°  

Also, ∠B = ∠D   .... Opposites angles of a parallelogram.  

∠A + ∠B + ∠C + ∠B = 360°  

37° + 2 ∠B + 37° = 360°  

74° + 2 ∠B = 360°  

2 ∠B = 360° - 74°  

2 ∠B = 286°  

∠B = 286 /2  

∠B = 143°  

∠B = ∠D = 143°  

So, the angles of the given parallelogram are 37° , 143° , 37° and 143°