Question

In parallelogram ABCD m∠A = (8x+8) and m∠C = (9x-7) find the measures of m∠B and m∠D?

Answer 1

$\bf \huge \underline {\underline{ANSWER}}$

For any parallelogram abcd, the formula for the lengths of the diagonals are, p=√x2+y2−2xycosA=√x2+y2+2xycosB p = x 2 + y 2 − 2 x y cos ⁡ A = x 2 + y 2 + 2 x y cos ⁡ B and q=√x2+y2+2xycosA=√x2+y2−2xycosB q = x 2 + y 2 + 2 x y cos ⁡ A = x 2 + y 2 − 2 x y cos ⁡

Answer 2

Step-by-step explanation:

estion 1:

In a parallelogram ABCD, ∠A =x°, ∠B = 3x +20°, find x and find ∠C and ∠D.

ANSWER:

In parallelogram ABCD, ∠A and ∠B are adjacent angles supplementary to each other.

Thus, we have:

∠A + ∠B = 180°

Also,

∠A = x° and ∠B = (3x + 20)°

⇒ x° + 3x° + 20° = 180°

⇒ 4x° + 20° = 180°

⇒ 4x° = 160°

⇒ x° = 40°

⇒ x = 40

We know that opposite angles of a parallelogram are congruent.

Thus, we have:

∠C = ∠A = x°

⇒∠C= 40°

∠D = ∠B

⇒ ∠D = 3x° + 20°

= 3(40°) + 20°

= 120° + 20°

= 140°

∴∠D=140°