Question

In parallelogram ABCD , P is the mid point of AB. CP and BD intersect each other at point O. If area of triangle POB = 40cm2, find :
{i} OP: OC
{ii} areas of triangles BOC and PBC .
{iii} areas of triangle ABC and parallelogram ABCD.

Answer 1

In triangle POB

area (POB) = 1/2 * PO * OB
40   = 1/2 * PO * OB
PO * OB = 80

also we cam see that

OC = 2 OB
Thus
PO/OC = 1
hence the first part is proved

Answer 2

Answer:

Step-by-step explanation:

In triangle POB

area (POB) = 1/2 * PO * OB

40   = 1/2 * PO * OB

PO * OB = 80

also we cam see that

OC = 2 OB

Thus

PO/OC = 1

hence the first part is proved