in parallelogram abcd, x is the midpoint of side dc and dz is drawn parallel to xb which meets cb produced at z and cut side ab at t prove that da= (1/2)cz and dz = 2 xb
Answers
Answered by
0
da= (1/2)cz and dz = 2 xb Proved for parallelogram ABCD x is the mid point of side dc & dx is drawn parallel to xb Which meets cb produced at z
Step-by-step explanation:
da= (1/2)cz and dz = 2 xb
dz is drawn parallel to xb
=> ΔCXB ≈ ΔCDZ
=> CX/CD = CB/CZ = XB/DZ
x is the mid point of side dc
=> CX/CD = 1/2
=> 1/2 = CB/CZ = XB/DZ
=> CZ = 2CB & DZ = 2XB
CZ = 2CB
=> CB = CZ/2
CB = DA ( opposite sides of Parallelogram)
=> DA = CZ/2
Learn More:
In a parallelogram ABCD, M and N are the mid-points
https://brainly.in/question/13131263
ABCD is a parallelogram
https://brainly.in/question/12950881
Similar questions