Question

In parallelogram GHKM, GH=6 cm and height from MK to GH is 10.5 cm. Find

a) Area of GHKM

b) If HK= 9 cm, find MO

Answer 1

Answer:

$a)area \: of \: ghkm \: = base \times height \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6 \times 10.5 = 63\\ b)hk \: is \: the \: base \: of \: parallelogram \: when \: mo \: is \: height \: \\ so \: area = hk \times mo \\ 63 = 9 \times mo \\ \frac{63}{9 } = mo \\ 7cm= mo$