Question

In parallelogram PQRS angle Q = (4x -5) degree , and angle S =(3x + 10)degree . Calculate : angle Q and angle R

Answer 1

We know that, in a parallelogram sum of inert angles is 180
Therefore, Angle Q +Angle S =180
4x-5+3x+10=180
7x+5=180
7x=180-5
7x=175
x=175/7
x=25
Therefore, Angle Q =4*25-5=100-5=95
Angle S =3*25+10=75+10=85....
Hope you got the satisfying answer...