In parallelogram PQRS angle Q = (4x -5) degree , and angle S =(3x + 10)degree . Calculate : angle Q and angle R
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We know that, in a parallelogram sum of inert angles is 180
Therefore, Angle Q +Angle S =180
4x-5+3x+10=180
7x+5=180
7x=180-5
7x=175
x=175/7
x=25
Therefore, Angle Q =4*25-5=100-5=95
Angle S =3*25+10=75+10=85....
Hope you got the satisfying answer...
Therefore, Angle Q +Angle S =180
4x-5+3x+10=180
7x+5=180
7x=180-5
7x=175
x=175/7
x=25
Therefore, Angle Q =4*25-5=100-5=95
Angle S =3*25+10=75+10=85....
Hope you got the satisfying answer...
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