Question

in parallelogram pqrs bisectors of angle q and p are in ratio 3:7 . find measure of angle roq and angle orq - oqr
​

Answer 1

PQRS is a parallelogram, P and Q  the bisector

we have to find out the measure of angle roq

∠ RQO = ∠OQR

∠SPO = ∠OPQ

∠R +∠S = 180° ( PQ║SR)

1/2∠R+ ∠Q = 180°/2

∠ORQ + ∠OQR = 90°

In Δ RQO -

∠OQR + ∠ORQ + ∠ROQ =180°

90°+ ∠ROQ = 180°

∴∠ROQ = 90°

there fore  ∠ROQ = 90°

Answer 2

Given that:

PQRS is a parallelogram, P and Q  the bisector,

and angle q and p in ratio 3:7.

We have to find out the measure of angle roq

∠ RQO = ∠OQR

∠SPO = ∠OPQ

∠R +∠S = 180° ( PQ║SR)

1/2∠R+ ∠Q = 180°/2

∠ORQ + ∠OQR = 90°

In Δ RQO -

∠OQR + ∠ORQ + ∠ROQ =180°

90°+ ∠ROQ = 180°

∴∠ROQ = 90°

there fore  ∠ROQ = 90°

∴The measure of angle roq is 90°