Question

in parallelogram PQRS Q 4x-5, S 3x plus 10, find angle Q and R​

Answer 1

as we all know that the opp sides of parallelogram are congruent so the given measures will be equal to each other

i.e. 4x-5=3x+10
so x=15

Now the angles are,
Q=4(15)-5=55^

and S=55^

Answer 2

Q and S are same opposite angles.

$4x - 5 = 3x + 10 \\ 4x - 3x = 15 \\ x = 15$

Then angle Q

$= 4x - 5 \\ = 4(15) - 5\\ = 60 - 5 \\ = 55$

Define angle R as x

angle Q + angle X = 180

$55 + x = 180 \\ x = 180 - 55 \\ x = 125$

angle X = angle R = 125

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