in pentagon two angles are 40and 60 and rest are in the ratio 1:3:7 find the biggest angle of pentagon
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heyyy
let angels be 1x,3x,7x,40&60
sum of angle of pentagon=540
1x+3x+7x+40+60=540
11x+100=540
11x=540 - 100
11x=440
x = 440/11
x=40
therefore it's angles are:
1x= 1*40=40,
3x=3*40=120,
7x=7*40=280,
60&40
Hence the biggest angle is 280
HOPE IT WILL HELP:-)
let angels be 1x,3x,7x,40&60
sum of angle of pentagon=540
1x+3x+7x+40+60=540
11x+100=540
11x=540 - 100
11x=440
x = 440/11
x=40
therefore it's angles are:
1x= 1*40=40,
3x=3*40=120,
7x=7*40=280,
60&40
Hence the biggest angle is 280
HOPE IT WILL HELP:-)
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