in photoelectric experiment ultraviolet write off 337 nm who is directed at the piece of potassium metal. the kinetic energy of the electrons ejected were measured as 2.30 × 10^-19J find binding energy for potassium.
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Answer:
3.59 * 10^-19 J
Explanation:
Apply Einstein's photoelectric equation,
KE = hc/lambda - Work function
Work funtion can also be called binding energy.
lambda is the wavelength of the light.
c is speed of light = 3 * 10^8 m/s
h is planck's constant = 6.626 * 10^-34
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