Question

In photosynthesis, 6 molecules of carbon dioxide combine with an equal
number of water molecules through a complex series of reactions to give a
molecule of glucose having a molecular formula C6H12O6. How many
grams of water would be required to produce 18g of glucose? Compute the
volume of water so consumed assuming the density of water to be 1g/cm3

Answer 1

Answer:

1.8g of H20

Explanation:

18g of H20 gives 180g of glucose

?? gives 18g of glucose

=18×18÷180 =1.8g of H20

hope u'll understand this concept follow me for best ans.

Answer 2

Answer:

10.8cm

3

Explanation:

6CO

2

+6H

2

O

Chlorophyll

Sunlight

C

6

H

12

O

6

+6O

2

1 mole of glucose requires 6 moles of water.

180 g of glucose requires (618) g of water.

1 g of glucose will require

180

108

g of water.

18 g of glucose would need

180

108

18g of water =10.8 g

Volume of water used =

Density

Mass

=

1g cm

−3

10.8g

=10.8cm

3