Question

In ∆PQR and equilateral ∆ABC, X is the midpoint of AC and PQ, Y is the midpoint of AB
and QR. If PR = 4 cm, find the perimeter of trapezium XYBC.

Answer 1

Answer:

Correct option is

B

14.2 cm

Given: X and Y are mid points of AB and AC respectively.

In △ABC, using mid point theorem

XY∥BC and XY=  

2

1

​  

BC

Thus, XY=3 cm

Since, D is mid point of AB , BX=  

2

1

​  

AB=  

2

1

​  

(5.4)=2.7 cm

Also, E is mid point of AC, CY=  

2

1

​  

AC=  

2

1

​  

(5)=2.5 cm

Now, Perimeter of XYCB = XY+YC+BC+XB

Perimeter of XYCB = 3+2.5+6+2.7

Perimeter of XYCB = 3+2.5+6+2.7 = 14.2 cm

Step-by-step explanation: