Question

In ∆PQR, angle PQR = 90° . state the Pythagorean relation in the triangle​

Answer 1

Step-by-step explanation:

Angle PQR =90° means angle Q=90°

therefore side opp. to Q is hypotenuse that is side PR and remaining sides are PQ and QR

Hence In ΔPQR,PR^2=PQ^2 + QR^2

Pls thank me

Answer 2

Answer:

The Pythagorean relation in the triangle is PR² = PQ² + QR²

Step-by-step explanation:

Here, it is given to us that the triangle PQR  = 90°

which means, that the triangle PQR is right angled at Q

therefore, angle Q = 90°

By Pythagoras Theorem,

we know that the hypotenuse lies opposite to the right angled corner of the triangle.

Hence, the hypotenuse  = PR

and the respective height of the triangle PQR = PQ

as well as then base is given by QR

So, we know that : (hypotenuse)² = (height)² + (base)²

Hence from the triangle PQR, we get :

PR² = PQ² + QR²

Therefore, the Pythagorean relation in the triangle is PR² = PQ² + QR²

#SPJ2