Question

In ∆PQR bisector of < Q and < R intersect at point O . If < P = 90* then find the measure of < QOR​

Answer 1

Answer:

135°

Step-by-step explanation:

<P= 90°

<P+<Q+<R=180° (sum of all the angles of a triangle)

Therefore, 90° +<Q+<R =180°

<Q+<R=90°

In triangle QOR,

<Q+<R+<O =180°( sum of all the angles of a triangle)

Now the angle bisector divides the value of <Q and <R to half it's value

Therefore, (<Q+<R) /2 = 45° - - - - i

From i,

45° + <O= 180°

<O =° 135 °

Therefore <QOR=135°