Question

In ∆pQR <p=2<Q and 2<R =3<Q ,calculate the angles of ∆PQR​

Answer 1

answer:

In ΔPQR, ∠P = 2*∠Q and, 2*∠R = 3*∠Q

We know that sum of three angle 180 degree. i.e ∠P + ∠Q + ∠R = 180

∠Q = ∠P/2.............................(1)

And, ∠R = 3*∠Q /2

 or, ∠R = 3*∠P/4...............................(2)

Then, from the values of (1) and (2), ∠P + ∠P/2 + 3*∠P/4 = 180

Or, ∠P* (1 + 1/2 + 3/4) = 180

Or, ∠P = 80

From (1), ∠Q = 40 and from (2) ∠R = 60.

Answer: ∠P = 80, ∠Q = 40, ∠R = 60.