In ∆ PQR, ∠ P= (3x+1°), ∠ Q = 2x, ∠ R = (2x+4°). Find the measure of each angle.
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Answered by
0
Answer:
∠ P= 76 ∠ Q= 50 ∠ R= 54
Step-by-step explanation:
Since it is in a triangle, ∠ P + ∠ Q + ∠ R = 180
Thus, 3x+1 +2x+2x+4 = 180
7x+5=180
7x=175
x=25
∠ P= (3x+1°)=76, ∠ Q = 2x = 50, ∠ R = (2x+4°) = 54
Answered by
0
Answer:
∠ p = 76°
∠ q = 50°
∠ r = 54°
Step-by-step explanation:
∠p = 3x + 1
∠q = 2x
∠r = 2x + 4
sum of all angles in a triangle = 180 degrees
∠p + ∠q + ∠r = 180
∴ 3x + 1 + 2x + 2x + 4 = 180
7x + 5 = 180
7x = 180 - 5
7x = 175
x = 175 / 7
x = 25
∠ p = 3x + 1
3 ( 25) + 1
76°
∠q = 2x
2 ( 25)
50°
∠ r = 2x + 4
2 ( 25 ) + 4
54°
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