Math, asked by surabhimishra590, 1 month ago

In ∆ PQR, ∠ P= (3x+1°), ∠ Q = 2x, ∠ R = (2x+4°). Find the measure of each angle.​

Answers

Answered by jacksuiziyuan0625
0

Answer:

∠ P= 76  ∠ Q= 50 ∠ R= 54

Step-by-step explanation:

Since it is in a triangle, ∠ P + ∠ Q + ∠ R = 180

Thus, 3x+1 +2x+2x+4 = 180

7x+5=180

7x=175

x=25

∠ P= (3x+1°)=76, ∠ Q = 2x = 50, ∠ R = (2x+4°) = 54

Answered by weirdlysarcastic101
0

Answer:

∠ p = 76°

∠ q = 50°

∠ r  = 54°

Step-by-step explanation:

∠p = 3x + 1

∠q = 2x

∠r = 2x + 4

sum of all angles in a triangle = 180 degrees

∠p + ∠q + ∠r = 180

∴ 3x + 1 + 2x + 2x + 4 = 180

  7x + 5 = 180

  7x = 180 - 5

  7x = 175

   x = 175 / 7

   x = 25

∠ p = 3x + 1

         3 ( 25) + 1

        76°

∠q = 2x

       2 ( 25)

       50°

∠ r = 2x + 4

        2 ( 25 ) + 4

        54°

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