In △PQR , ∠P - ∠Q = 18° and ∠Q - ∠R = 12° . Find all the 3 angles of the triangle.
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<P-<Q=18. (1)
<Q-<R=12. (2)
From equation (1)
<P=18+<Q. (3)
We know that sum of all angles of triangle is 180
then <P+<Q+<R=180
putting the value of <P in this equation
18+<Q+<Q+<R=180
=2<Q+<R=180-18
then from equation (2) we get
<R=<Q-12 putting this value in that equation
=2<Q+<Q-12=162
=3<Q=162+12
=<Q=174/3
=<Q=58
then putting this value in equation (1)
<P-<Q=18
<P- 58=18
then <P= 58+18
<P=76
then putting this value in equation (2)
<Q-<R=12
58-<R=12
<R=46
then angles are 76, 58 ,46
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