In ∆pqr ,pe perpendicular bisector of QPR , Prove that PQ=QR.
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In ∆PEQ and ∆ PER
PE=PE( common)
ang.QPE=ang.RPE (as PE bisects ang.QPR)
ang.QEP=ang.REP (each 90°)
Therefore ∆PEQ≈∆PER by AAS rule
By CPCT PQ=PR
Hope this helps
PE=PE( common)
ang.QPE=ang.RPE (as PE bisects ang.QPR)
ang.QEP=ang.REP (each 90°)
Therefore ∆PEQ≈∆PER by AAS rule
By CPCT PQ=PR
Hope this helps
akshitha0123:
Tu hi kar lo na
Answered by
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Given
PE is perpendicular bisector of QPR
PE=RE
To prove = PQ=QR
proof - In triangle PEQ and triangle PER
(s) PE = RE - GIVEN
(A) PEQ = PER =90 BOTH ARE 90
(S) PE = PE COMMON
So, ΔPEQ ≈ ΔPER by SAS rule
Also, PQ = QR BY CPCT
PE is perpendicular bisector of QPR
PE=RE
To prove = PQ=QR
proof - In triangle PEQ and triangle PER
(s) PE = RE - GIVEN
(A) PEQ = PER =90 BOTH ARE 90
(S) PE = PE COMMON
So, ΔPEQ ≈ ΔPER by SAS rule
Also, PQ = QR BY CPCT
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