In ∆pqr ,pe perpendicular bisector of QPR , Prove that PQ=QR.
Answers
Answered by
2
In ∆PEQ and ∆ PER
PE=PE( common)
ang.QPE=ang.RPE (as PE bisects ang.QPR)
ang.QEP=ang.REP (each 90°)
Therefore ∆PEQ≈∆PER by AAS rule
By CPCT PQ=PR
Hope this helps
PE=PE( common)
ang.QPE=ang.RPE (as PE bisects ang.QPR)
ang.QEP=ang.REP (each 90°)
Therefore ∆PEQ≈∆PER by AAS rule
By CPCT PQ=PR
Hope this helps
akshitha0123:
Tu hi kar lo na
yarr plz ladies first
U msg me
yarr mere mobile me nahi ho raha h plz ik barr tu kar
Ok 5 min toko
ok
hello
Hi
hii
Come to inbox or bye
Answered by
0
Given
PE is perpendicular bisector of QPR
PE=RE
To prove = PQ=QR
proof - In triangle PEQ and triangle PER
(s) PE = RE - GIVEN
(A) PEQ = PER =90 BOTH ARE 90
(S) PE = PE COMMON
So, ΔPEQ ≈ ΔPER by SAS rule
Also, PQ = QR BY CPCT
PE is perpendicular bisector of QPR
PE=RE
To prove = PQ=QR
proof - In triangle PEQ and triangle PER
(s) PE = RE - GIVEN
(A) PEQ = PER =90 BOTH ARE 90
(S) PE = PE COMMON
So, ΔPEQ ≈ ΔPER by SAS rule
Also, PQ = QR BY CPCT
Similar questions