Math, asked by nn684, 9 months ago

In ∆PQR PQ=4cm QR=9cm and PR=15cm.Is ∆PQR a right angled triangle? If yes, which angle is 90°?

Answers

Answered by prakhar5166
1

Answer:

Step-by-step explanation:

PQ^2 + QR^2 = PR^2

16 + 81 = 225

97 is not equal to 225.

Therefore, It is not a Right Angled Triangle.

Answered by presthadahal
0

Answer:

In triangle PQR,

  • PQ is 4cm
  • QR is 4cm
  • PR is 15cm

Now,

         

from above point look closely, the longer side are always hypotenuse

thus PR is hypotenuse. So, PQ and QR are legs. Therefore, if PQR is right angled triangle Q is be  90degree.

Then,

Let's check whether triangle PQR is a right angle triangle by Pythagoras

Theorem.

(hypotenuse)^2= (base)^2 + (height)^2

LHS= (hypotenuse)^2

      = 15^2

      = 225

RHS= (base)^2 + (height)^2

      = 4^2 + 4^2

      = 16 + 16

      = 32

Therefore, triangle PQR is not a right right angle because LHS is not equal to RHS

 

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