Math, asked by princebisht, 8 months ago

In ∆ PQR , PQ=PR and ext. ∠PRS =135 degree . then ∠P is​

Answers

Answered by challapavani1988
5

Answer:

90°

Step-by-step explanation:

in triangle PQR ,Angle PRS is an external angle which lies joining to angle PRQ and also PRQ = PQR angles

so PRQ +PRS = 180 °

PRQ = 180°- 135°=45°

PRQ = PQR = 45°

PQR +PRQ+RPQ =180°

45°+45°+ANGLE P = 180°

ANGLE P = 180 ° - 90°

ANGLE P= 90°

Hope you understand this .......

Answered by kavyaclass9
7

Answer:

The answer is 90°

Step-by-step explanation:

is the opposite sides are equal the opposite angles are also equal

so,  ∠PQR =  ∠PRQ

∠PRS + ∠PRQ = 180 (linear pair)

135 + ∠PRQ = 180

∠PRQ = 180-135 = 45°

now, ∠PQR = ∠PRQ

∠PQR = 45°

∠PQR + ∠PRQ + ∠QPR = 180 (Angle Sum Property)

45 + 45 + ∠QPR = 180

∠QPR = 180 - (45 + 45)

∠QPR = 90°

Therefore, ∠P = 90°

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