Question

In ∆ PQR, PQ = PR and <QPR = 80°, then <PRQ is
i) 50°,
ii) 60°;
iii) 70°;
iv) 80°​

Answer 1

50°

80+x+x=180

80+2x=180

2x=180-80

2x=100

x=100/2

x=50

Answer 2

Answer:

Step by step explanation:

Given, QPR = 80°, and PQ = PR

let the other two angles be x, x

because it is an isosceles triangle.

by triangle sum property

80+ x + x = 180°

2x + 80 = 180°

2x = 180° - 80

2x = 100

x = 100/2

x = 50

Please Mark Me As Brainiest