In ∆ PQR ,PT is a bisector of angle QPR,Q_T_ R if PQ= 6 cm , PR= 9 cm then find QT : TR ?
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PT bisects ∠PQR,
Thus,
QT
PQ
=
RT
PR
4
5.6
=
5
x
x=
4
5.6×5
x=7 cm
Perimeter = PQ + QR + PR
Perimeter = 5.6 + 5 + 4 + 7
Perimeter=21.6 cm
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