In ∆PQR ,Q=70 outer angle PRS=105 ,Q=70 find P ?
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PQR =70
outer PRS = 105
PRQ = 180-105 = 75 (sum of external and interior angle is 180)
QPR + QRP + PQR = 180
QPR = 180 -(70+75)
QPR = 180-145 = 35
outer PRS = 105
PRQ = 180-105 = 75 (sum of external and interior angle is 180)
QPR + QRP + PQR = 180
QPR = 180 -(70+75)
QPR = 180-145 = 35
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