In ΔPQR , ∠Q = 90°, PR= 29cm and QR= 21cm, find PQ ?
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Given
- A ΔPQR,
- ∠Q = 90°
- PR = 29 cm
- QR = 21 cm
To find
- PQ = ? cm
Solution
- In ΔPQR, ∠Q = 90°
- PQ² = PR² - QR² (Pythagoras Theorem)
- PQ² = 29² - 21²
- PQ² = 841 - 441
- PQ² = 400
- PQ = √400
- PQ = 20 cm
☯ Length of PQ = 20 cm
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