Question

In ∆PQR ∠Q=90°, ∠R=30°,PR=10cm the find the side PQ and QR​

Answer 1

Answer:

cos30° = QR/PR

√3/2= QR/10

=>QR= 10√3/2= 5√3

again

sin30°= PQ/PR

1/2=PQ/10

=>PQ=10/2=5