Question

In ∆PQR , right angled at Q . lf the length of PQ = 63 cm and PR = 65 cm . find the length of QR​

Answer 1

Answer:

Using Pythagors Theorem,

(PR)^2 = (PQ)^2 + (QR)^2

(65)^2 = (63)^2 + QR^2  

QR^2 = 4225 - 3969

QR^2 = 256

QR = root of 256

QR = 16cm

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Answer 2

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