in ∆ PQR sides PR and QR are extended to B and A respectively if angle ARB equal to 62 degree find angle PRQ and BRQ
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∠ARB=∠PRQ= 62 (vertucalky opposite angles are equal)
∠BRQ+∠ARP+∠ARB+∠PRQ=360
∠BRQ+∠BRQ+62+62=360
2∠BRQ=360-124
∠BRQ=236/2=118
∠BRQ+∠ARP+∠ARB+∠PRQ=360
∠BRQ+∠BRQ+62+62=360
2∠BRQ=360-124
∠BRQ=236/2=118
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