Question

In Python, what kind of error is returned by the following code? (e.g. NameError, ValueError, IOError, etc.) def my_func(n1, n2): return n1 + n2 my_func(1, 2, 3)

Answer 1

Answer:

Type error

Explanation:

Let the code be tried the code with Python 3.6.4

Thus, after using the return in my_func ahead of the call of my_func, then you will get -

$ python3

Python 3.6.4 (default, Jan  7 2018, 15:53:53)

[GCC 6.4.0] on cygwin

Type "help", "copyright", "credits" or "license" for more information.

>> def my_func (n1, n2): return n1+n2

>> my_func (1, 2, 3)

Traceback (most recent call last):

File "<stdin>", line 1, in <module>

TypeError: my_func() takes 2 positional arguments but 3 were given

>>>

Therefore, the error returned is Type error.

Answer 2

Answer:

Explanation:

In Python, Type Error error is returned by the following code (e.g. NameError, ValueError, IOError, etc.): def my_func (n1, n2): return n1+n2 my_func (1, 2, 3). It would show the error termed as invalid syntax. The correct format would be the following code -

>>> def my_func (n1, n2):

...     return n1+n2

...     my_func (1, 2, 3)

Here, the my_func never gets called at all.