Chemistry, asked by aarushijain18, 2 months ago

In Q1, if [Zn2+] = 0.1 M and [Cu2+] = 0.01 M, calculate the EMF of the cell

Q1. The electrodes reduction potentials of Zn and Cu electrodes are 0.76 and +0.34
V respectively.

Answers

Answered by crazymonsatar008

0

Explanation:

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