in quad. abcd angle b-a=c-b=b-d. if a = 60, find all angles.
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from above relation we can conclude that angles are in arithmetic progression with first term a and let the common difference be x
and we know that sum of all angles of a quadrilateral is 360
let ,
a+a+x+a+2x+a+3x = 360
6x = 120
x = 20
angles are a = 60 , b = 80 , c = 100 , d = 120
and we know that sum of all angles of a quadrilateral is 360
let ,
a+a+x+a+2x+a+3x = 360
6x = 120
x = 20
angles are a = 60 , b = 80 , c = 100 , d = 120
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