.In quadrilateral ABCD,∠A=∠C=119°,∠B=∠D=61°.State which pair of sides of those given below is parallel.
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Answered by
0
Answer:
Since the sum of any two consecutive angles of a parallelogram is 180
o
. Therefore,
∠A+∠D=180
o
and ∠A+∠B=180
o
Now, ∠A+∠D=180
o
∠A+115
o
=180
o
∠A=65
o
and, ∠A+∠B=180
o
65
o
+∠B=180
o
∠B=115
o
Thus, ∠A=65
o
and ∠B=115
o
.
Answered by
0
7+3=10
78
79
80
21
23
24
25
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