Math, asked by gamersamson242, 13 hours ago

.In quadrilateral ABCD,∠A=∠C=119°,∠B=∠D=61°.State which pair of sides of those given below is parallel.​

Answers

Answered by rumaorigin15
0

Answer:

Since the sum of any two consecutive angles of a parallelogram is 180

o

. Therefore,

∠A+∠D=180

o

and ∠A+∠B=180

o

Now, ∠A+∠D=180

o

∠A+115

o

=180

o

∠A=65

o

and, ∠A+∠B=180

o

65

o

+∠B=180

o

∠B=115

o

Thus, ∠A=65

o

and ∠B=115

o

.

Answered by riyanmallick43
0

7+3=10

78

79

80

21

23

24

25

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