Question

In quadrilateral ABCD, AB = 40 cm. BC = 35 cm, CD = 48 cm,
DA = 29 cm and BD = 29 cm. Find the area of quadrilateral
ABCD.​

Answer 1

Answer:

please send in Kannada

Answer 2

Answer:

78√14

Step-by-step explanation:

in triangle ABD

semi perimeter(s)=(29+29+40)/2=49

therefore,√(49-29)(49-29)(49-40)=60cm^2

In triangle BCD

semi perimeter(s)=(48+35+29)/2=56

therefore,√(56-48)(56-35)(56-29)=18√14

total area=60+18√14=78√14

=294.8492(approx.)

this is solved by herons formula