in quadrilateral ABCD AB=BC, angleB=60°
CD = 4 cm, AD= 3 cm. Find area of AB CD
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Answer:
let CD is a length of quardilareral is 4cm
and AD is breadth of quardilatetal is 3cm
area of quardilateral =length*breadth
=CD*AD
=4*3
=12 cm
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