in quadrilateral ABCD , AB || CD & AD || BC prove that angle ABC || ADC
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Since AB || DC and AD is the transversal
⇒ ∠BAD + ∠ADC = 180° …. (Consecutive interior angles) …(i)Again AD || BC and AB is the transversal ⇒ ∠DAB + ∠ABC = 180° ….(ii)Comparing eqns (i) and (ii), we get⇒ ∠BAD + ∠ADC = ∠DAB + ∠ABC ... ∠ADC = ∠ABC
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