in quadrilateral ABCD ,AC=AD and AB bisect angel A . show that ∆ ABC=∆ABD . what can you say about BC and BD
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Answered by
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ABCD is a quadrilateral.
In triangle ABC & triangle ABD,
AC=AD (given)
<BAC=<BAD (as it is given that AB bisects <A)
AB is common
Therefore, triangle ABC =triangle ABD
BC=BD (by CPCT)
Hope it may help you....
In triangle ABC & triangle ABD,
AC=AD (given)
<BAC=<BAD (as it is given that AB bisects <A)
AB is common
Therefore, triangle ABC =triangle ABD
BC=BD (by CPCT)
Hope it may help you....
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Laddle123:
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Answered by
12
Solutions:
In △ABC and △ABD, we have
AC = AD ........... [Given]
∠CAB = ∠DAB ........ [Since, AB is the bisector of ∠DAC]
and,. AB = AB ............ [Common]
So, by SAS congruence rule, we obtain
△ABC ≅ △ABD
=> BC = BD .......... [By c.p.c.t.]
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