In quadrilateral ABCD angle A:angleB:angle C: angle D = 3:4:5:6 show that AB parallel CD
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Let the angles of quadrilateral ABCD are 2x,3x,4x and 6x
We know, sum of angles of quadrilateral is 360
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∴ ∠A+∠B+∠C+∠D=360
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⇒ 2x+3x+4x+6x=360
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⇒ 15x=360
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∴ x=24
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⇒ ∠A=2x=2×24
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=48
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⇒ ∠B=3x=3×24
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=72
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⇒ ∠C=4x=4×24
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=96
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⇒ ∠D=6x=6×24
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=144
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Step-by-step explanation:
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