In quadrilateral ABCD angle B=90 angle C-angle D=60 and AngleA-angleC-angleD=10. Then angle A;C;D=?
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Answer:
answer is here.
Step-by-step explanation:
b=90
a-c-d=10
c-d=60
a-60=10
a=70
a+b+c+d=360
90+70+c+d=360
160+c+d=360
c+d=360-160
c+d= 200
c-d=60
by cancelling d=0
2c=260
c=130
c+d =200
130+d=200
d=70
so,a=70,b=90,c=130 and d=70.
please mark it as brainiest
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