In quadrilateral ABCD, angle C=44°, angle d=angle c-20°, angle a=(3a-4)° and angle b= (2a+6)°.
Calculate angle a and angle b.
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angle c=44° therefore
d=44°-20°=24°
we know that sum of all angles of quadrilateral=360°
so
a+b+c+d=360°
24°+44°+a+b=360°
a+b=292°
3a-4+2a+6=292°
5a+2=292°
5a=292-2
5a=290°
a=290°÷5
a=58°
b=2×58°+6
b=122°
a=3a-4
a= 170°
d=44°-20°=24°
we know that sum of all angles of quadrilateral=360°
so
a+b+c+d=360°
24°+44°+a+b=360°
a+b=292°
3a-4+2a+6=292°
5a+2=292°
5a=292-2
5a=290°
a=290°÷5
a=58°
b=2×58°+6
b=122°
a=3a-4
a= 170°
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