In quadrilateral ABCD, ∠BAC=50°, ∠BCA=25°,∠DAC=25° and ∠DCA=50°. Is ΔABC≅ΔCDA? Give reasons
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Answer:
Here ∠BDC=∠BAC=50
∘
since angles in same segment are equal
In △BCD, we have
∠BCD=180
∘
−(∠BDC+∠DBC)
=180
∘
−(50
∘
+60
∘
)
=180
∘
−110
∘
=70
∘
∴∠BCD=70
∘
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