IN QUADRILATERAL ABCD SHOWN IN THE FIGURE AB PARALLEL CD AND DA - AB ALSO AB=8 M BC=5 M AND CD=5M FIND THE AREA OF THE QUADRILATERIAL IN TWO WAYS:TAKING ABCD AS A TRAPEZIUM &TAKING QUADRILATERIAL ABCD as the sum of rectangle AECD+TRIANGLE BEC
Answers
Area of Quadrilateral ABCD = 26 m²
Step-by-step explanation:
AB ║ CD
DA ⊥AB
AB = 8 m
BC = 5 m
CD = 5 m
Let say CE ⊥ AB
=> AE = CD = 5 m
BE = AB - AE = 8 - 5 = 3 cm
CE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cm
Area of Trapezium = (1/2)(AB + CD) * CE
= (1/2)(8 + 5) * 4
= 13 * 2
= 26 m²
Area of Quadrilateral ABCD = Area of rectangle AECD + Area of Triangle BCE
Area of rectangle AECD = AE * CE = 5 * 4 = 20 m²
Area of Triangle BCE = (1/2)BE * CE = (1/2) * 3 * 4 = 6 m²
Area of Quadrilateral ABCD = 20 + 6 = 26 m²
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Answer:
here ,
area of R means area of rectangle
area of T means area of triangle
Step-by-step explanation:
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