in quadrilateral ABCD side BC parallel to side BD.diagonals AC and BD intersect each other at point P if AP=1/3 AC then prove that DP =1/2 BP
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ummm Ur Question is Wrong...
BC cannot Be parallel to BD unless BD and BC are Co-incident.. in which case it would Make ABCD a Triangle instead of a Quadrilateral...
Could you Repost The correct Question..
Someone would answer it for sure.
Regards,
Leukonov.
BC cannot Be parallel to BD unless BD and BC are Co-incident.. in which case it would Make ABCD a Triangle instead of a Quadrilateral...
Could you Repost The correct Question..
Someone would answer it for sure.
Regards,
Leukonov.
AMkhade:
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Wrong question answer ERROR
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