in quadrilateral ABCD, the Angles are in the ratio of 3:4:5:6.find the measure of each angle of the quadrilateral
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sum of interior angles of quadrilateral is 360 degrees
let the angles be 3x,4x,5x,6x
then 3x+4x+5x+6x=360
18x=360
x=20 degrees
3x=3(20)=60
4x=4(20)=80
5x=5(20)=100
6x=6(20)=120
let the angles be 3x,4x,5x,6x
then 3x+4x+5x+6x=360
18x=360
x=20 degrees
3x=3(20)=60
4x=4(20)=80
5x=5(20)=100
6x=6(20)=120
Answered by
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Let the angles be 3x,4x,5x,6x
So as we know that sum of all angles of a quadrilateral is 360
3x+4x+5x+6x=360
18x=360
x=360/18
x=20
So the angles are
3x=60
4x=80
5x=100
6x=120
So as we know that sum of all angles of a quadrilateral is 360
3x+4x+5x+6x=360
18x=360
x=360/18
x=20
So the angles are
3x=60
4x=80
5x=100
6x=120
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