Question

In quadrilateral ACBD,
AC = AD and AB bisects ZA
(see Fig. 7.16). Show that A ABC=A ABD.
What can you say about BC and BD?

Answer 1

Answer:

proof_

AC=AD(given)

angle 1 = angle 2(ab bisects angle a)

AB=AB(common)

therefore, triangle ABC IS CONGURENT TO TRIANGLE ADC BY C .P.C.T

Answer 2

Given : AC = AD and AB bisects angle a

To prove :△ ABC ≅△ABD

Proof : In △ABC and △ABD

AC = AD ( given )

∠CAB = ∠DAC ( AB is a bisector)

AB = AB (. common)

By SAS Congruence △ABC ≅△ABD

We can say that by cpct BC = BD

Proved