Question

in quardic equation

Answer 1

3y^2+2y^2=160+20
5y^2=180
y^2=36
y=-+6
is your answer

Answer 2

3y^2-20=160-2y^2
3y^2+2y^2=160+20
5y^2=180
y^2=180/5
y^2=36
y=√36
y=+-6

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