Question

In questions 2 and 3 find the total area of the shape. OA = 2cm,OB = 3cm,OC = 5cm,OD = 3cm

Answer 1

Answer:

OC is perpendicular on chord AB

∴OC bisects the chord AB

⇒AC=CB

Now,

AC+CB=AB

⇒AC+CB=8

⇒AC=

2

8

⇒4cm

△OCA is a right angled triangle

∴AO

2

=AC

2

+OC

2

⇒5

2

=4

2

+OC

2

⇒5

2

−4

2

=OC

2

⇒OC

2

=9

⇒OC=3

Since, OD is the radius of the circle

∴OA=OD=5cm

CD=OD−OC

⇒5−3=2cm